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- Discrete mathematics
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- ISE II
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- Q.1 prove that following boolean identities. a * (a' + b) = a * b
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- a * (a' + b) = a * b here, * = . (ie, and gate) + = + = (ie, and gate) LHS = a * (a' + b) = a . (a' + b) = a.a' + a.b (distributive low) = 0+ a.b (identity low) = a.b = a*b = RHS.
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- Q2. Prove [(A→B)∧A]→B is a tautology
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- As we can see every value of [(A→B)∧A]→B is "True", it is a tautology.
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- THANKT YOU....