Question 4

Question 4

Published on 1 July 2020

MAT183 VIDEO ASSGMENT CALCULUS SEM 4

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Transcript
00:04
MAT183
00:13
QUESTION 4
00:22
Find the minimum surface area of the container
00:43
2
00:43
Area = (πr   + 2πrh) + (πrl)
00:60
j=x=2.31
01:04
l=3x=6.93
01:08
h=3.03
01:13
=[π(2.31) + 2π(2.31)(3.03)] + [π(2.31)(6.93)]
01:13
2
01:40
= (60.74) + (50.29)
01:48
=111.03 cm
01:48
2